## RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles VSAQS

These Solutions are part of RD Sharma Class 9 Solutions. Here we have given RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles VSAQS

**Other Exercises**

- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles Ex 10.1
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles Ex 10.2
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles Ex 10.3
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles Ex 10.4
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles VSAQS
- RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles MCQS

**Question 1.
**

**Define complementary angles.**

**Solution:**

Two angles whose sum is 90°, are called complementary angles.

**Question 2.
**

**Define supplementary angles.**

**Solution:**

Two angles whose sum is 180°, are called supplementary angles.

**Question 3.
**

**Define adjacent angles.**

**Solution:**

Two angles which have common vertex and one arm common are called adjacent angles.

**Question 4.
**

**The complement of an acute angles is…….**

**Solution:**

The complement of an acute angles is

**an acute angle.**

**Question 5.
**

**The supplement of an acute angles is………**

**Solution:**

The supplement of an acute angles is

**a obtuse angle.**

**Question 6.
**

**The supplement of a right angle is…….**

**Solution:**

The supplement of a right angle is

**a right angle.**

**Question 7.
**

**Write the complement of an angle of measure x°.**

**Solution:**

The complement of x° is (90° – x)°

**Question 8.
**

**Write the supplement of an angle of measure 2y°.**

**Solution:**

The supplement of 2y° is (180° – 2y)°

**Question 9.
**

**If a wheel has six spokes equally spaced, then find the measure of the angle between two adjacent spokes.**

**Solution:**

Total measure of angle around a point = 360°

Number of spokes = 6

∴ Angle between the two adjacent spokes = \(\frac { { 360 }^{ \circ } }{ 6 }\) = 60°

**Question 10.
**An angle is equal to its supplement. Determine its measure.

**Solution:**

Let required angle = x°

Then its supplement angle = 180° – x

x = 180° – x

⇒ x + x = 180°

⇒ 2x = 180° ⇒ x = \(\frac { { 180 }^{ \circ } }{ 2 }\) = 90°

∴ Required angle = 90°

**Question 11.**

**An angle is equal to five times its complement. Determine its measure.
**

**Solution:**

Let required measure of angle = x°

∴ Its complement angle = 90° – x

∴ x = 5(90° – x)

⇒ x = 450° – 5x

⇒ x + 5x = 450°

⇒ 6x = 450°

⇒ x = \(\frac { { 450 }^{ \circ } }{ 6 }\) = 75°

∴ Required angle = 75°

**Question 12.
**

**How many pairs of adjacent angles are formed when two lines intersect in a point?**

**Solution:**

If two lines AB and CD intersect at a point O, then pairs of two adjacent angles are, ∠AOC and ∠COB, ∠COB and ∠BOD, ∠BOD and DOA, ∠DOA and ∠ZAOC

i.e, 4 pairs

Hope given RD Sharma Class 9 Solutions Chapter 10 Congruent Triangles VSAQS are helpful to complete your math homework.

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